8x^2-4=-20

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Solution for 8x^2-4=-20 equation: 



8x^2-4=-20

We move all terms to the left:

8x^2-4-(-20)=0

We add all the numbers together, and all the variables

8x^2+16=0

a = 8; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·8·16
Δ = -512
Delta is less than zero, so there is no solution for the equation

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